A capacitor charged to `50 V` is discharged by connecting the two plates at `t=0`.If the potential difference across the plates drops to 1.0 V at t=10 ms,what will be the potential difference at t=20 ms?

Explanation

To solve the problem step by step, we will use the formula for the discharging of a capacitor in an RC circuit:

### Step 1: Understand the formula for discharging a capacitor
The voltage across a discharging capacitor at time \( t \) is given by:
\[ V(t) = V_0 e^{-\frac{t}{RC}} \]
where:
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