A battery of emf 100V and a resistor of resistance `10k(Omega)`are joined in series. This system is used as a source to supply current to an external resistance R. If R is not greater than `100(Omega)`, the current through it is constant up to two significant digits. Find its value, This is the basic principle of a constant-current source.

Explanation

To solve the problem step-by-step, we will follow the principles of series circuits and Ohm's law.

### Step 1: Identify the components and their values
- The electromotive force (emf) of the battery, \( V = 100 \, \text{V} \)
- The resistance of the internal resistor, \( R_1 = 10 \, \text{k}\Omega = 10,000 \, \Omega \)
- The external resistance, \( R \), which is not greater than \( 100 \, \Omega \).

### Step 2: Calculate the total resistance in the circuit
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