A wire of resistance `15.0(Omega)`is bent to form a regular hexagon ABCDEFA.Find the equivalent resistance of the loop between the points (a)A and B, (b)A and C and (c )A and D .

Explanation

To solve the problem of finding the equivalent resistance of a wire bent into a regular hexagon, we will follow these steps:

### Step 1: Determine the Resistance of Each Side
The total resistance of the wire is given as \( R = 15.0 \, \Omega \). Since the wire is bent into a regular hexagon, it has 6 equal sides. Therefore, the resistance of each side of the hexagon can be calculated as:
\[ R_{\text{side}} = \frac{R}{6} = \frac{15.0 \, \Omega}{6} = 2.5 \, \Omega \]

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