A voltmeter coil has resistance `50.0(Omega)`and a resistor of `1.15k(Omega)`is connected in series.It can read potential differences upto 12 volts.If this same coil is used to construct an ammeter which can measure currents up to 2.0A ,What should be the resistance of the shunt used ?

Explanation

To solve the problem step by step, we will follow these calculations:

### Step 1: Determine the Effective Resistance of the Voltmeter
The voltmeter coil has a resistance of \( R_v = 50 \, \Omega \) and a series resistor of \( R_s = 1.15 \, k\Omega = 1150 \, \Omega \).

The effective resistance \( R_{eff} \) of the voltmeter is given by:
\[
R_{eff} = R_v + R_s = 50 \, \Omega + 1150 \, \Omega = 1200 \, \Omega
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