A parallel-plate capacitor with plate are `20cm^(2)`and plate separation 1.0mm is connected to a battery .The resistance of the circuit is `10k(Omega)`.Find the time constant of the circuit.

Explanation

To find the time constant of the circuit with a parallel-plate capacitor, we will follow these steps:

### Step 1: Identify the given values
- Area of the plates, \( A = 20 \, \text{cm}^2 = 20 \times 10^{-4} \, \text{m}^2 \)
- Plate separation, \( d = 1.0 \, \text{mm} = 1.0 \times 10^{-3} \, \text{m} \)
- Resistance of the circuit, \( R = 10 \, k\Omega = 10 \times 10^3 \, \Omega \)

### Step 2: Calculate the capacitance \( C \) of the parallel-plate capacitor
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