A capacitor of capacitance `10(mu)F` is connected to a battery of emf 2V.It is found that it takes 50 ms for the charge on the capacitor to bacome `12.6(mu)C.`find the resistance of the circuit.

Explanation

To solve the problem step by step, we will use the formula for the charging of a capacitor in an RC circuit:

### Step 1: Identify the given values
- Capacitance, \( C = 10 \, \mu F = 10 \times 10^{-6} \, F \)
- EMF of the battery, \( V = 2 \, V \)
- Charge on the capacitor at time \( t = 50 \, ms = 50 \times 10^{-3} \, s \)
- Charge on the capacitor, \( Q = 12.6 \, \mu C = 12.6 \times 10^{-6} \, C \)

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