A `20(mu)F`capacitor is joined to a battery of emf 6.0V through a resistance of `100(Omega)`.find the charge on the capacitor 2.0ms after the connections are made .

Explanation

To solve the problem of finding the charge on a capacitor after a certain time when connected to a battery through a resistor, follow these steps:

### Step 1: Identify the given values
- Capacitance, \( C = 20 \, \mu F = 20 \times 10^{-6} \, F \)
- EMF of the battery, \( V = 6.0 \, V \)
- Resistance, \( R = 100 \, \Omega \)
- Time, \( t = 2.0 \, ms = 2.0 \times 10^{-3} \, s \)

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