Home
Class 12
PHYSICS
A current of 30 A is registered when the...

A current of `30 A` is registered when the terminals of a dry cell of EMF 1.5 VOLTS are connected through an ammeter. Neglecting the meter resistance, find the amount of heat produced in the battery in 10 seconds.

Text Solution

AI Generated Solution

To find the amount of heat produced in the battery in 10 seconds when a current of 30 A is flowing through it, we can follow these steps: ### Step 1: Identify the given values - Current (I) = 30 A - EMF (E) = 1.5 V - Time (t) = 10 seconds ### Step 2: Calculate the resistance of the circuit ...
Promotional Banner

Topper's Solved these Questions

  • THERMAL AND CHEMICAL EFFECT OF ELECTRIC CURRENT

    HC VERMA ENGLISH|Exercise Objective 1|6 Videos

  • THERMAL AND CHEMICAL EFFECT OF ELECTRIC CURRENT

    HC VERMA ENGLISH|Exercise Objective 2|5 Videos

  • THERMAL AND CHEMICAL EFFECT OF ELECTRIC CURRENT

    HC VERMA ENGLISH|Exercise Short Question|9 Videos

  • THE SPECIAL THEORY OF RELATIVITY

    HC VERMA ENGLISH|Exercise Short answer|2 Videos

  • X-Rays

    HC VERMA ENGLISH|Exercise Ques for Short Ans|10 Videos

Similar Questions

Explore conceptually related problems

A battery has an open circuit potential difference 10 V between the terminals. When loads 9Omega and 4 Omega are connected one by one across the battery , the power in the load resistance is the same. The amount of heat approximately generated in one second in the load when a load of 5Omega Is connected across the battery will be

The poten tial difference between the terminals of a cells is found to be 3 volts when it is connected to a resistance equal to its internal resistance. The e.m.f. of the cell is:-

The resistance of the rheostat shown in figure is 30(Omega) . Neglecting the meter resistance,find the minimum and maximum currents through the ammeter as the rheostat is varied.

A galvanometer of 50 Omega resistance when connected across the terminals of a battery of emf 2V along with the resistance 200 Omega the deflection produced in the galvanometer is 10 divisions. If the total number of divisions on the galvanometer ·scale on either side of central zero is 30, then the maximum current that can pass through the galvanometer is

An accumulator of emf 2 V and negligible internal resistance is connected across a uniform wire of length 10 m and resistance 30 Omega The appropriate terminals of a cell of emf 1.5 V and internal resistance 1 Omega is connected to one end of the wire and the other terminal of the cell is connected through a sensitive galvanometer to a slider on the wire. What is the length of the wire that will be required to produce zero deflection of the galvanometer? How will the balancing length change? (a) When a coil of resistance 5Omega is placed in series with the accumulator. (b) The cell of 1.5 V is shunted with 5 Omega resistor?

A storage battery with emf 2.6 V loaded with external resistance produces a current 1 A . In this case, the potential difference between the terminals of the storage battery equals 2 V . Find the thermal power generated in the battery and the net power supplied by the battery for external circuit.

A current of 2 A flows through a 2 Omega resistor when connected across a battery. The same battery supplies a current of 0.5 A when connected across a 9 Omega resistor. The internal resistance of the battery is

A current of 2 A flows through a 2 Omega resistor when connected across a battery. The same battery supplies a current of 0.5 A when connected across a 9 Omega resistor. The internal resistance of the battery is

In a potentiometer experiment it is found that no current passes through the galvanometer when the terminals of the cell are connected across 0.52 m of the potentiometer wire. If the cell is shunted by a resistance of 5Omega balance is obtained when the cell connected across 0.4m of the wire. Find the internal resistance of the cell.

In a potentiometer experiment it is found that no current passes through the galvanometer when the terminals of the cell are connected across 0.52 m of the potentiometer wire. If the cell is shunted by a resistance of 5Omega balance is obtained when the cell connected across 0.4m of the wire. Find the internal resistance of the cell.