An electric bulb, when connected across a power supply of `220V`, consumes a power of `60 W`. If the supply drops supply is suddently increased to `240 V`, what will be the power consumed?

Explanation

To solve the problem step by step, we will follow these calculations:

### Step 1: Identify the initial conditions
We know that:
- Initial voltage, \( V_0 = 220 \, \text{V} \)
- Initial power, \( P_0 = 60 \, \text{W} \)

### Step 2: Calculate the resistance of the bulb
Using the formula for resistance based on power and voltage:
\[ R = \frac{V^2}{P} \]
Substituting the initial values:
\[ R = \frac{(220)^2}{60} \]
Calculating this:
\[ R = \frac{48400}{60} \approx 806.67 \, \Omega \]

### Step 3: Identify the new voltage
The new voltage after the increase is:
\[ V_1 = 240 \, \text{V} \]

### Step 4: Calculate the new power consumed
Using the power formula again, where the resistance remains constant:
\[ P = \frac{V^2}{R} \]
Substituting the new voltage and the calculated resistance:
\[ P = \frac{(240)^2}{806.67} \]
Calculating this:
\[ P = \frac{57600}{806.67} \approx 71.4 \, \text{W} \]

### Step 5: Final answer
Thus, the power consumed by the bulb when the voltage is increased to 240 V is approximately:
\[ \boxed{71 \, \text{W}} \]