A magnetic field of `(4.0 X10^(-3)vec k)` T exerts a force of `(4.0veci +3.0vecj x 10^(-10)` N on a particle having a charge of `1.0X10^(-9)` C and going in the x-y plane. Find the velocity of the particle.

Explanation

To solve the problem, we need to find the velocity of a charged particle moving in a magnetic field. The force exerted on the particle is given, and we can use the equation for the magnetic force on a charged particle.

### Step-by-Step Solution:

1. **Identify Given Values:**
- Magnetic field, \( \vec{B} = 4.0 \times 10^{-3} \hat{k} \) T
- Force, \( \vec{F} = (4.0 \hat{i} + 3.0 \times 10^{-10} \hat{j}) \) N
- Charge, \( q = 1.0 \times 10^{-9} \) C
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