A current of 2 A enters at the corner d of a square frame abcd of side 20 cm and leaves at the opposite corner b. A magnetic field B= 0.1 T exists in the space in a direction perpenducular to the plane of the frame as shown in Find the magnitude and direction of the magnetic forces on the four sides of the frame.

Explanation

In wire do,
` F _dz =n ijB sin 90 @ `
` (2 )/(2) xx 20 xx 10 ^(-2) xx 0.1 `
` = 0.02 N toward left `
in wire ab ,
` F_ab = ijB sin 90@ `
` = (2) /(2) xx 20 xx 10^(-2) xx 0.1 towards downward `
` = 0.02` toward downwards.
Similarly , we can get e force in DC and cb wire .