A particle having a charge of `2.0X10^(-8) C` and a mass of `2.0X10^(-10)g` is projected with a speed of `2.0X10^3 ms^(-1)` in a region having a uniform magnetic field of 0.10 T. The velocity is perpendicular to the field. Find the radius of the circle formed by the particle and also the time period.

Explanation

To solve the problem step by step, we will first identify the given values, then calculate the radius of the circular path of the charged particle in the magnetic field, and finally calculate the time period of the motion.

### Step 1: Identify the Given Values
- Charge of the particle, \( Q = 2.0 \times 10^{-8} \, \text{C} \)
- Mass of the particle, \( m = 2.0 \times 10^{-10} \, \text{g} = 2.0 \times 10^{-10} \times 10^{-3} \, \text{kg} = 2.0 \times 10^{-13} \, \text{kg} \)
- Speed of the particle, \( v = 2.0 \times 10^{3} \, \text{m/s} \)
- Magnetic field strength, \( B = 0.10 \, \text{T} \)

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