A charged particle is accelerated thrught a potential difference of 12 kV and acquires a speed of `1.0X10^6 ms^(-1).` It is then injected perpendiuclarly into a magnetic field of strenght 0.2 T. find the radius of the circle described by it.

Explanation

To solve the problem step by step, we will follow the outlined process to find the radius of the circle described by the charged particle in the magnetic field.

### Step 1: Understand the Given Information
- The potential difference (V) through which the charged particle is accelerated is 12 kV (which is 12,000 V).
- The speed (v) acquired by the particle after acceleration is \(1.0 \times 10^6 \, \text{m/s}\).
- The magnetic field strength (B) is 0.2 T (Tesla).

### Step 2: Calculate the Charge-to-Mass Ratio
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