A proton is projected with a velocity of `3X10^6 m s ^(-1)` perpendicular to a uniform magnetic field of 0.6 T. find the acceleration of the proton.

Explanation

To solve the problem of finding the acceleration of a proton projected perpendicular to a magnetic field, we can follow these steps:

### Step 1: Identify Given Values
We have the following values:
- Velocity of the proton, \( v = 3 \times 10^6 \, \text{m/s} \)
- Magnetic field strength, \( B = 0.6 \, \text{T} \)
- Charge of the proton, \( q = 1.6 \times 10^{-19} \, \text{C} \)
- Mass of the proton, \( m = 1.67 \times 10^{-27} \, \text{kg} \)
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