Fe^+ ions are accelerated through a potential difference of 500 V and are injected normally into a homogeneous magnetic field B of strength 20.0 m T. Find the radius of the circular paths followed by the isotopes with mass numbers 57 and 58. Take the mass of an `ion = A (1.6 X10^(-27)` kg where A is the mass number.

Explanation

To solve the problem of finding the radius of the circular paths followed by Fe^+ ions with mass numbers 57 and 58 when accelerated through a potential difference of 500 V and injected into a magnetic field of strength 20.0 mT, we can follow these steps:

### Step 1: Determine the mass of the ions
The mass of an ion is given by the formula:
\[ m = A \times (1.6 \times 10^{-27}) \text{ kg} \]
where \( A \) is the mass number.

For the isotope with mass number 57:
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