A particle moves in a circle of diamater 1.0 cm under the action of magnetic field of 0.40 T, An electric field of `200 V m^(-1)` makes the path straight. Find the charges/mass ratio of the particle.

Explanation

To find the charge-to-mass ratio (Q/m) of a particle moving in a circular path under the influence of a magnetic field and an electric field, we can follow these steps:

### Step-by-Step Solution:

1. **Identify Given Values**:
- Diameter of the circular path, \( d = 1.0 \, \text{cm} = 0.01 \, \text{m} \)
- Radius of the circular path, \( R = \frac{d}{2} = \frac{0.01}{2} = 0.005 \, \text{m} \)
- Magnetic field strength, \( B = 0.40 \, \text{T} \)
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