A proton projected in a magnetic field of 0.020 T travels along a helical path of radius 5.0 cm and pitch 20 cm. Find the components of the velocity of the proton along and perpendicular to the magnetic field. Take the mass of the proton` =1.6X10^(-27)`kg.

Explanation

To solve the problem of a proton projected in a magnetic field, we need to find the components of its velocity along and perpendicular to the magnetic field. Let's break this down step by step.

### Step 1: Understand the Given Information
- Magnetic field strength (B) = 0.020 T
- Radius of the helical path (r) = 5.0 cm = 0.05 m
- Pitch of the helix (p) = 20 cm = 0.20 m
- Mass of the proton (m) = 1.6 x 10^(-27) kg
- Charge of the proton (q) = 1.6 x 10^(-19) C
...