A long, straight wire carrying a current of 1.0 A is placed horizontally in a uniform magnetic field B= (`1.0 xx 10^-5)` T pointing vertically upward. Find the magnitude of the resultant magnetic field at the points P and Q, both situated at a distance of 2.0 cm from the wire in the same horizontal plane.

Explanation

Given that uniform magnetic field, ` B = 1.0 xx106(-5)T`
`. (Pointing vertically upward) So net magnetic field at point P ` B = 2xx1.0 xx 10^(-5) T`
`. `= 20 muT` `
`. Net magnetic field at Q `B'' = 0`