A straight , long wire carries a current a current of 20A. Another wire carrying equal current is placed parallel to it. If the force acting on a length of 10cm of the second wire is `(2.0 xx (10^-5)) N`, what is the separation between them?

Explanation

To solve the problem, we need to find the separation between two parallel wires carrying equal currents. We can use the formula for the magnetic force between two parallel wires.

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Current in each wire, \( I = 20 \, \text{A} \)
- Length of the second wire, \( L = 10 \, \text{cm} = 0.1 \, \text{m} \)
- Force acting on the second wire, \( F = 2.0 \times 10^{-5} \, \text{N} \)
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