Figure shows a part of an electric circuit. The wires AB, CD, and EF are long and have identical resistances. The separation between the neighbouring wires is 1.0 cm. The wires AE and BF have negligible resistances and the ammeter reads 30 A . Calculate the magnetic force per unit length of AB and CD. `

Figure shows a part of an electric circuit. ABCD is a rectangular loop made of uniform wire. The length AD= BC = 1 cm. The sides AB and DC are long as compared to the other two sides. Find the magnetic force per unit length acting on the wire DC due to the wire AB if the ammeter reads 10A.

What is the resistance between P and Q in the following circuit? Each resistance is of 1 Omega and the wire between eb and bd have resistance 0.5Omega each.

The force per unit length between two parallel current carrying wires = (mu_(0)i_(1)i_(2))/(2pir) . The force is attractive when the current is in same direction and repulsive, when the they are in opposite directions. The force between the wires of two parallel wires is shown. We can determine the equilibrium position. Then we displace upper wire by a small distance, keeping lower wire fixed. If the wire returns to or tries to return to its equilibrium position, its equilibrium is stable. We can thus show that upper wire can execute linear simple harmonic motion or not. The length of wire AB is large as compared to separation between the wires. If wire CD is displaced upward to increase the separation by dh, the magnitude of net force per unit length acting on the wire CD becomes

In a potentiometer circuit, the emf of driver cell is 2V and internal resistance is 0.5 Omega . The potentiometer wire is 1m long . It is found that a cell of emf 1V and internal resistance 0.5 Omega is balanced against 60 cm length of the wire. Calculate the resistance of potentiometer wire.

The circuit diagram shown in Fig includes a 6 V battery, an ammeter A, a fixed resistor R_I of 2 Omega and a resistance wire R_2 connected between the terminals A and B. The resistance of the battery and ammeter may be neglected. Calculate the ammeter readings when the wire R_2 is of 0.20 m length and of resistance 4 Omega .

The circuit diagram shown in Fig includes a 6 V battery, an ammeter A, a fixed resistor R_I of 2 Omega and a resistance wire R_2 connected between the terminals A and B. The resistance of the battery and ammeter may be neglected. Calculate the ammeter readings when the wire R_2 is of 0.20 m length and of area of cross section double than that in case (a).

The resistance per unit length of the wires in segments AB, BC, CD, and AD are the same. The magnetic field due to the current at point O is

Three coplanar parallel wires, each carrying a current of 10 A along the same direction, are placed with a separation 5.0 cm between the consecutive ones. Find the magnitude of the magnetic force per unit length acting on the wires.

Two identical batteries, each having emf of 1.8 V and of equal internal resistances are connected as shown in the figure. Potential difference between A and B will be equal to (Ignore the resistance of lead wires)

A potentiometer circuit is shown in Figure 3 below. AB is a uniform metallic wire having length of 2m and resistance of 8Omega . The batteries E_(1) and E_(2) have emfs of 4V and 1.5V and their internal resistances are 1Omega and 2Omega respectively. Now the jockey J is made to touch the wire AB at a point C such that the galvanometer (G) shows no deflection. Calculate the length AC.