A charge of `(3.14 xx 10^-6)` C is distributed uniformly over a circular ring of radius 20.0 cm. The ring rotates about its axis with an angular velocity of 60.0 rad ` s^-1 . Find the ratio of the electric field to the magnetic field at a point on the axis at a distance of 5.00 cm from the centre.

Explanation

To solve the problem of finding the ratio of the electric field to the magnetic field at a point on the axis of a rotating charged ring, we can follow these steps:

### Step 1: Identify the given values
- Charge \( q = 3.14 \times 10^{-6} \, \text{C} \)
- Radius of the ring \( r = 20.0 \, \text{cm} = 0.2 \, \text{m} \)
- Distance from the center of the ring to the point of interest \( x = 5.0 \, \text{cm} = 0.05 \, \text{m} \)
- Angular velocity \( \omega = 60.0 \, \text{rad/s} \)

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