Home
Class 12
PHYSICS
A tangent galvanometer has 66 turns and ...

A tangent galvanometer has 66 turns and the diameter of its coil is 22cm. It gives a deflection of `45^@ for 0.10 ` A current. What is the value of the horizontal component of the earth's magnetic field?

Text Solution

AI Generated Solution

To find the horizontal component of the Earth's magnetic field (Bh) using the information provided about the tangent galvanometer, we will follow these steps: ### Step 1: Identify the given data - Number of turns (n) = 66 - Diameter of the coil (d) = 22 cm = 0.22 m - Radius of the coil (r) = d/2 = 0.22 m / 2 = 0.11 m - Deflection angle (θ) = 45° - Current (I) = 0.10 A ...
Promotional Banner

Topper's Solved these Questions

  • PERMANENT MAGNETS

    HC VERMA ENGLISH|Exercise Worker out examples|19 Videos

  • PERMANENT MAGNETS

    HC VERMA ENGLISH|Exercise Objective|13 Videos

  • OPTICAL INSTRUMENTS

    HC VERMA ENGLISH|Exercise Question for short Answer|12 Videos

  • PHOTO ELECTRIC EFFECT AND WAVE PARTICLE DUALITY

    HC VERMA ENGLISH|Exercise question for short answer|13 Videos

Similar Questions

Explore conceptually related problems

At a place, the horizontal component of earth's magnetic field is B and angle of dip is 60^@ . What is the value of horizontal component of earth's magnetic field at equator?

At a place, the horizontal component of earth's magnetic field is V and angle of dip is 60^(@) . What is te value of horizontal component of earth's magnetic field at equator ?

A tangent galvanometer shown a deflection of 45^@ when 10 mA of current is passed through it. If the horizontal component of the earth's magnetic field is B_H = 3.6 xx 10^(-5) T and radius of the coil is 10cm , find the number of turns in the coil.

Earth's magnetic field always has a horizontal component except at

A circular coil of radius 20 cm and 20 turns of wire is mounted vertically with its plane in magnetic meridian.A small magnetic needle (free to rotate about vertical axis) is placed at the center of the coil.It is deflected through 45^(@) when a current is passed through the coil and in equilbrium (Horizontal component of earth's field is 0.34 xx 10^(-4) T ).The current in coil is:

A circuit coil of radius 20 cm and 20 turns of wire is mounted vertically withits plane in the magnetic meridian. A small magnetic needle placed at the center of the coil is deflected through 45^(@) when a current is passed through the coil. What is the value of the current? (horizontal induction of earth's field = 3.6xx10^(-5)Wb//m^(2)

At the magnetic north pole of the earth, the value of horizontal component of earth's magnetic field and angle of dip are, respectively

A tangent galvanometer has a coil with 50 turns and radius equal to 4 cm . A current of 0.1 A is passing through it. The plane of the coil is set parallel to the earth's magnetic meridian. If the value of the earth's horizontal component of the magnetic field is 7xx10^(-5) Tesla and mu_(0)=4pixx10^(-7)Weber//ampxxm then the deflection in the galvanometer needle will be

A magnetic needle is arranged at the centre of a current carrying coil having 50 turns with radius of coil 20cm arranged along magnetic meridian. When a current of 0.5mA is allowed to pass through the coil the deflection is observed to be 30°. Find the horizontal component of earth's magnetic field

A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north tip pointing down at 22^@ with the horizontal. The horizontal component of the earth's magnetic field at the place is known to be 0*35G . Determine the strength of the earth's magnetic field at the place.