A bar magnet of mass 100 g, length 7.0 cm, width 1.0 cm and height 0.50 cm takes `pi/2` seconds to complete an oscillation in an oscillation magnetometer placed in a horizontal magnetic field of `25 muT`. (a) Find the magnetic moment of the magnet. (b) If the magnet is put in the magnetometer with its `0.50cm` edge horizontal, what would be the time period?

Explanation

To solve the problem step by step, we will break it down into two parts: (a) finding the magnetic moment of the magnet and (b) calculating the new time period when the magnet is placed with its 0.50 cm edge horizontal.

### Part (a): Finding the Magnetic Moment

1. **Identify Given Values:**
- Mass of the magnet (m) = 100 g = 0.1 kg (convert grams to kilograms)
- Length of the magnet (L) = 7.0 cm = 0.07 m (convert cm to m)
- Width of the magnet (W) = 1.0 cm = 0.01 m (convert cm to m)
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