Home
Class 12
PHYSICS
The current in a discharging LR circuit ...

The current in a discharging `LR` circuit is given by `I = i_0 (t/tau)` where `tau` is the time constant of the circuit. Calculate the rms current for the period `t = 0` to `t = tau`.

Text Solution

AI Generated Solution

To calculate the RMS current for the period \( t = 0 \) to \( t = \tau \) in a discharging LR circuit where the current is given by \( I = I_0 \frac{t}{\tau} \), we will follow these steps: ### Step 1: Understand the RMS Current Definition The RMS (Root Mean Square) current is defined as: \[ I_{\text{RMS}} = \sqrt{\frac{1}{T} \int_0^T I^2 \, dt} \] where \( T \) is the time period over which we are calculating the RMS value. ...
Promotional Banner

Topper's Solved these Questions

  • ALTERNATING CURRENT

    HC VERMA ENGLISH|Exercise Objective 1|11 Videos
  • ALTERNATING CURRENT

    HC VERMA ENGLISH|Exercise Objective 2|7 Videos
  • ALTERNATING CURRENT

    HC VERMA ENGLISH|Exercise Short answer|14 Videos
  • BOHR'S MODEL AND PHYSICS OF THE ATOM

    HC VERMA ENGLISH|Exercise Short Answer|10 Videos

Similar Questions

Explore conceptually related problems

The current in a discharging LR circuit is given by I = i_0 e^(-t/tau) where tau is the time constant of the circuit. Calculate the rms current for the period t = 0 to t = tau .

The electric curren in a charging R-C circuit is given by i=i_0e^(-t/RC) when i_0 , R and C aere constant parameters of the circuit and t is time. Find the rate of change of current at a. t=0, b. t=RC c. t=10RC .

The current in a discharging LR circuit without the battery drops from 2.0 A to 1.0A in 0.10 s. (a) find the time constant of the circuit. (b) if the inductance of the circuit is 4.0 H, what is its resistance?

The current in an AC circuit is given by I = I_0 sin (50 pi )/t where t is in second. The time interval in which it will reach from zero to its peak value is

The electric current in a circuit is given by i=3t Here, t is in second and I in ampere. The rms current for the period to=0 to t=1 s is

The electric current in a discharging R-C circuit is given by i=i_0e^(-t/(RC)) where i_0 R and C are constant parameters and t is time. Let i_0=2.00A , R=6.00xx10^5 ohm and C=0.500 muF . a. Find the current at t=0.3 s. b. Find the rate of change of current at t=0.3 s. Find approximately the current at t=0.31 s.

The voltage supplied to a circuit is given by V=V_(0)t^(3/2) , where t is time in second. Find the rms value of voltage for the period, t=0 to t=1s.

Current in an ac circuit is given by I= 3 sin omega t + 4 cos omega t, then

In an LR circuit, current at t=0 is 20A . After 2s it reduced to 18A. The time constant of the circuit is (in second)

Show that time constant (tau = RC) of R - C circuit has the dimensions of time.