Home
Class 12
PHYSICS
An inductor coil joined to a 6 V battery...

An inductor coil joined to a `6 V` battery draws a steady current of `12 A`. This coil is connected to a capacitor and an `AC` source of rms voltage `6 V` in series. If the current in the circuit is in phase with the emf, find the rms current.

Text Solution

AI Generated Solution

To solve the problem step by step, we will analyze the given information and apply the relevant formulas. ### Step 1: Understand the Given Information - We have an inductor coil connected to a 6 V battery that draws a steady current of 12 A. - The coil is then connected to a capacitor and an AC source of RMS voltage 6 V in series. - The current in the circuit is in phase with the EMF. ### Step 2: Identify the Parameters ...
Promotional Banner

Topper's Solved these Questions

  • ALTERNATING CURRENT

    HC VERMA ENGLISH|Exercise Objective 1|11 Videos
  • ALTERNATING CURRENT

    HC VERMA ENGLISH|Exercise Objective 2|7 Videos
  • ALTERNATING CURRENT

    HC VERMA ENGLISH|Exercise Short answer|14 Videos
  • BOHR'S MODEL AND PHYSICS OF THE ATOM

    HC VERMA ENGLISH|Exercise Short Answer|10 Videos

Similar Questions

Explore conceptually related problems

An inductor coil is connected to a 12V battery and drawing a current 24 A. This coil is connected to capacitor and an AC source of rms voltage rating 24 V in the series connection. The rms current through the circuit would found to be

A 6 V, 12 W lamp is connected in series with a resistor R and a source of voltage 12 V. What is the current flowing through the circuit?

A 200Omega resistor is connected to a 220 V, 50 Hz AC supply. Calculate rms value of current in the circuit. Also find phase difference between voltage and the current.

In an AC circuit , an alternating voltage e = 200√2 sin 100t V is connected to a capacitor of capacity 1mu F . The rms value of the current in the circuit is

A long solenoid connected to a 12V DC source passes a steady current of 2 A. When the solenoid is connected to an AC source of 12V at 50 Hz, the current flowing is 1A. Calculate inductance of the solenoid.

When an inductor coil is connected to an ideal battery of emf 10V, a constant current 2.5 A flows. When the same inductor coil is connected to an ac source of 10V and 50 HZ then the current is 2A. Find out the inductance of the coil.

A battery of emf 12V and internal resistance 2Ω is connected with two resistors A and B of resistance 4Ω and 6Ω respectively joined in series. . The current i in the circuit is

A coil having a resistance of 50.0 Omega and an inductance of 0.500 henry is connected to an AC source of 110 volts, 50.0 cycle/s. Find the rms value of the current in the circuit.

A 30 mu F capacitor is connected to a 150 V, 60 Hz ac supply. The rms value of current in the circuit is

An inductor coil carries a steady state current of 2.0 A when connected across an ideal battery of emf 4.0 V. if its inductance is 1.0 H, find the time constant of the circuit.