An AC source is connected to a capacitor. Will the rms current increase, decrease or remain constant if a dielectric slab is inserted into the capacitor?

An AC source is connected to a capacitor. The current in the current is I. Now a dielectric slab is inserted into the capacitor , then the new current is

A variable frequency AC source is connected to a capacitor. How will the displacement current change with decrease in frequency?

A variable frequency AC source is connected to a capacitor. How will the displacement current change with decrease in frequency?

A capacitor and a bulb are connected in series with a source of alternating emf. If a dielectric slab is inserted between the plates of the capacitor, then

Consider these three statements for a capacitor STATEMENT-1 : Capacitance of a capacitor must increase when a dielectric is inserted in between the capacitor plates. STATEMENT-2 : Potential differenece across a charged capacitor must increase if a dielectric is inserted in between the capacitor plates. STATEMENT-3 : Electrostatic energy stored by the capacitor may increase if a dielectric inserted in between the capacitor plates

Assertion : Resonance frequency will decrease in L-C-R series circuit if a dielectric slab is inserted in between the plates of the capacitor. Reason : By doing so, capacity of capacitor will increase.

If a variable frequency ac source is connected to a capacitor then with decrease in frequency the displacement current will

A parallel plate capacitor is connected across a battery. Now, keeping the battery connected, a dielectric slab is inserted between the plates. In the process,

A parallel plate capacitor is connected to a battery of emf V volts. Now a slab of dielectric constant k=2 is inserted between the plates of capacitor without disconnecting the battery. The electric field between the plates of capacitor after inserting the slab is E= (PV)/(2d) . Find the value of P.

A parallel capacitor of capacitance C is charged and disconnected from the battery. The energy stored in it is E . If a dielectric slab of dielectric constant 6 is inserted between the plates of the capacitor then energy and capacitance will become.