An AC source is rated `220 V, 50 Hz`. The average voltage is calculated in a time interval of `0.01 s`. It

Options

A. must be zero
B. may be zero
C. is never zero
D. is `(220/(sqrt 2)) V`

Answer

To solve the problem step by step, we need to find the average voltage of an AC source over a specified time interval. Here’s how we can approach it:

### Step 1: Understand the AC Source Ratings
The AC source is rated at 220 V and 50 Hz. The voltage provided is the RMS (Root Mean Square) voltage, which is commonly used in AC circuits.

### Step 2: Calculate the Time Period of the AC Source
The frequency (f) of the AC source is given as 50 Hz. The time period (T) can be calculated using the formula:
\[ T = \frac{1}{f} \]
Substituting the given frequency:
\[ T = \frac{1}{50} = 0.02 \text{ seconds} \]

### Step 3: Analyze the Given Time Interval
We need to calculate the average voltage over a time interval of 0.01 seconds.

### Step 4: Determine the Relationship Between Time Interval and Time Period
The time interval of 0.01 seconds is half of the time period (0.02 seconds). Since the average voltage over a complete cycle (one time period) is zero, we need to check if the given time interval is an integral multiple of the time period.

### Step 5: Conclusion About the Average Voltage
The average voltage over a complete cycle (0.02 seconds) is zero. Since 0.01 seconds is not a complete cycle but rather half of it, the average voltage over this interval will not be zero.

Thus, we conclude that the average voltage calculated over the time interval of 0.01 seconds is never zero.

### Final Answer
The average voltage calculated in the time interval of 0.01 seconds is **never 0**.

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