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An alternating current is given by I =...

An alternating current is given by
`I = i_1 cos omegat + i_2 sin omegat`.
The rms current is given by

A

`(i_1 + i_2)/(sqrt2)`

B

`(|i_1 + i_2|)/(sqrt2)`

C

`sqrt((i_1^2 + i_2^2)/(2)`

D

`sqrt((i_1^2 + i_2^2)/(sqrt2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the RMS (Root Mean Square) current for the given alternating current \( I = i_1 \cos(\omega t) + i_2 \sin(\omega t) \), we can follow these steps: ### Step 1: Identify the components of the current The given current can be expressed as: \[ I = i_1 \cos(\omega t) + i_2 \sin(\omega t) \] Here, \( i_1 \) and \( i_2 \) are the amplitudes of the cosine and sine components, respectively. ### Step 2: Use the trigonometric identity To combine the two components, we can express the cosine function in terms of sine: \[ \cos(\omega t) = \sin\left(\omega t + \frac{\pi}{2}\right) \] Thus, we can rewrite the equation as: \[ I = i_1 \sin\left(\omega t + \frac{\pi}{2}\right) + i_2 \sin(\omega t) \] ### Step 3: Combine the sine terms Using the sine addition formula, we can combine these terms into a single sine function: \[ I = \sqrt{i_1^2 + i_2^2} \sin\left(\omega t + \phi\right) \] where \( \phi \) is the phase difference between the two components. ### Step 4: Calculate the RMS value The RMS value of a sinusoidal current is given by: \[ I_{\text{RMS}} = \frac{I_{\text{max}}}{\sqrt{2}} \] where \( I_{\text{max}} \) is the maximum (peak) current. In our case, the maximum current is: \[ I_{\text{max}} = \sqrt{i_1^2 + i_2^2} \] Thus, substituting this into the RMS formula gives: \[ I_{\text{RMS}} = \frac{\sqrt{i_1^2 + i_2^2}}{\sqrt{2}} = \frac{\sqrt{i_1^2 + i_2^2}}{2} \] ### Final Result Therefore, the RMS current is: \[ I_{\text{RMS}} = \frac{\sqrt{i_1^2 + i_2^2}}{\sqrt{2}} \]
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