The electric field in an electromagnetic wave is given by `E( 50 N C^-1) sin omega (t-x/c).` Find the energy contained in a cylinder of cross section 10 cm^2 and length 50 cm along the x- axis.

Explanation

To solve the problem, we need to find the energy contained in a cylinder of a given cross-section and length, given the electric field of an electromagnetic wave. Here’s a step-by-step breakdown of the solution:

### Step 1: Identify the given parameters
- The electric field amplitude \( E_0 = 50 \, \text{N/C} \)
- The cross-sectional area \( A = 10 \, \text{cm}^2 = 10 \times 10^{-4} \, \text{m}^2 = 1 \times 10^{-3} \, \text{m}^2 \)
- The length of the cylinder \( L = 50 \, \text{cm} = 0.5 \, \text{m} \)

### Step 2: Calculate the volume of the cylinder
...