Home
Class 12
PHYSICS
Show that the dimensions of the displace...

Show that the dimensions of the displacement current `(epsilon_0(d Phi_E)/dt)` are that of an electric current.

Text Solution

AI Generated Solution

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTROMAGNETIC WAVES

    HC VERMA ENGLISH|Exercise Question for short answers|7 Videos
  • ELECTROMAGNETIC INDUCTION

    HC VERMA ENGLISH|Exercise Questions for short answer|9 Videos
  • GAUSS LAW

    HC VERMA ENGLISH|Exercise Short Question|7 Videos

Similar Questions

Explore conceptually related problems

Displacement current flows in

Displacement current continues in a circuit,

Knowledge Check

  • A long straight cable of length l is placed symmetrically along z-axis and has radius a(ltlt l). The cable consists of a thin wire and a co- axial conducting tube. An alternating current I(t) = I_(0) " sin " (2pi vt) . Flows down the central thin wire and returns along the co-axial conducting tube. the induced electric at a distance s from the wire inside the cable is E(s ,t) =mu_(0) I_(0) v " cos "(2pivt) In ((s)/(a)) hatk . (i) Calculate the displacement current density inside the cable. (ii) Integrate the displacement current density across the cross- section of the cable to find the total displacement current I^(d) . (iii) compare the conduction current I_(0) with the displacement current I_(0)^(d) .

    A
    `(2pi)/(lamda^(2))I_(0)ln((a)/(s))sin(2pi upsilont)hat(k)`
    B
    `(1)/(lamda^(2))I_(0)ln((a)/(s))sin(2pi upsilont)hat(k)`
    C
    `(pi)/(lamda^(2))I_(0)ln((a)/(s))sin(2pi upsilon t)hat(k)`
    D
    Zero
  • Similar Questions

    Explore conceptually related problems

    Find the dimensions and units of epsilon_0

    Dimensions of epsi_(0) (dphi_(E))/(dt) are same as that of

    Dimensions of epsi_(0) (dphi_(E))/(dt) are same as that of

    The dimensions of epsilon_(0)mu_(0) are

    Write Maxwell's generalization of Ampere's Circuital Law. Show that in the process of charging a capacitor the , current produced within the plates of the capcitor is I = epsilon_(0) = (d Phi_(E))/(dt)" where " Phi_(E) is the electric flux produced during charging of the capacitor plates.

    (A ): When a capacitor is getting charged the conduction current in the connecting wires at any instant is equal to the displacement current in between the capacitor plates. (R) : Conduction current is always greater than the displacement current.

    If E denotes of electric field, the dimension of a quantity in_(0)(dE)/(dt) are those of