A diode, a resistor and a `50 Hz AC` source are connected in series. The number of current pulses per second through the resistor is

Options

A. 25
B. 50
C. 100
D. 200

Answer

To solve the problem, we need to determine the number of current pulses per second through the resistor when a diode, a resistor, and a 50 Hz AC source are connected in series.

### Step-by-Step Solution:

1. **Understand the Components**: We have a diode, a resistor, and an AC source connected in series. The AC source has a frequency of 50 Hz.

2. **Frequency of AC Source**: The frequency of an AC source indicates how many times the current changes direction in one second. A frequency of 50 Hz means that the current alternates 50 times per second.

3. **Function of the Diode**: A diode allows current to flow in only one direction. Therefore, during each cycle of the AC source, the diode will conduct current only during one half of the cycle (positive half-cycle) and block current during the other half (negative half-cycle).

4. **Current Pulses Through the Resistor**: Since the diode only allows current to pass during the positive half-cycle of the AC waveform, there will be one current pulse for each complete cycle of the AC source.

5. **Calculate Current Pulses**: Since the AC source has a frequency of 50 Hz, this means there are 50 complete cycles in one second. Therefore, there will be 50 current pulses through the resistor in one second.

6. **Final Answer**: The number of current pulses per second through the resistor is **50**.

### Summary:
The number of current pulses per second through the resistor is equal to the frequency of the AC source, which is 50 Hz. Thus, the answer is **50**.