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A beam of 450 nm light is incident on a ...

A beam of 450 nm light is incident on a metal having work function 2.0 eV and placed in a magnetic field B. The most energetic electrons emitted perpendicular to the field are bent in circular arcs of radius 20 cm. Find the value of B.

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To solve the problem, we will follow a step-by-step approach: ### Step 1: Calculate the Energy of the Incident Photons The energy of the incident photons can be calculated using the formula: \[ E = \frac{hc}{\lambda} \] Where: - \( h \) (Planck's constant) = \( 4.14 \times 10^{-15} \, \text{eV s} \) - \( c \) (speed of light) = \( 3 \times 10^{8} \, \text{m/s} \) ...
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