Home
Class 12
PHYSICS
Light described at a place by the equ...

Light described at a place by the equation `E=(100 V/m) [sin(5xx10^15 s ^(-1) )t +sin (8xx 10^15 s^(-1) )t]` falls on a metal surface having work function 2.0 eV. Calculate the maximum kinetic energy of the photoelectrons.

Text Solution

AI Generated Solution

To solve the problem, we need to calculate the maximum kinetic energy of the photoelectrons emitted from a metal surface when light described by the given equation falls on it. The equation of the light is: \[ E = (100 \, \text{V/m}) \left[ \sin(5 \times 10^{15} \, \text{s}^{-1} \, t) + \sin(8 \times 10^{15} \, \text{s}^{-1} \, t) \right] \] The work function of the metal is given as \( \phi = 2.0 \, \text{eV} \). ### Step-by-step Solution: ...
Promotional Banner

Topper's Solved these Questions

  • PHOTO ELECTRIC EFFECT AND WAVE PARTICLE DUALITY

    HC VERMA ENGLISH|Exercise objective I|14 Videos

  • PHOTO ELECTRIC EFFECT AND WAVE PARTICLE DUALITY

    HC VERMA ENGLISH|Exercise objective II|7 Videos

  • PHOTO ELECTRIC EFFECT AND WAVE PARTICLE DUALITY

    HC VERMA ENGLISH|Exercise question for short answer|13 Videos

  • PERMANENT MAGNETS

    HC VERMA ENGLISH|Exercise Short Answer|11 Videos

  • PHOTOMETRY

    HC VERMA ENGLISH|Exercise All Questions|38 Videos

Similar Questions

Explore conceptually related problems

Light described at a palce by te equation E=(100 V/m) [sinxx10^15 s ^(-1) t +sin (8xx 10^15 s^(-1) t] falls on a metal surface having work function 2.0 eV. Calcualte the maximum kinetic energy of the photoelectrons.

Light wave described by the equation 200 V//m sin (1.5xx10^15 s^(-1) t cos (0.5xx10^15 s^(-1) t falls metal surface having work function 2.0 eV. Then, the maximum kinetic energy photoelectrons is

The electric field at a point associated with a light wave is E=100Vm^-1 sin [(3*0xx10^15 s^-1)t] sin [(6*0xx10^15s^-1)t]. If this light falls on a metal surface having a work function of 2*0 eV , what will be the maximum kinetic energy of the photoelectrons?

The electric field of certain radiation is given by the equation E = 200 {sin (4pi xx 10^10)t + sin(4pi xx 10^15)t} falls in a metal surface having work function 2.0 eV. The maximum kinetic energy (in eV) of the photoelectrons is [Plank's constant (h) = 6.63 xx 10^(-34)Js and electron charge e = 1.6 xx 10^(-19)C]

Statement-1 : Light described at a place by the equation E= E_(0) (sin omegat + sin 7 omegat) falls on a metal surface having work funcation phi_(0) . The macimum kinetic energy of the photoelectrons is KE_(max) = (7homega)/(2pi) - phi_(0) Statement-2 : Maximum kinetic energy of photoelectron depends on the maximum frequency present in the incident light according to Einstein's photoelectric effect equation.

Light of wavelength 2000Å is incident on a metal surface of work function 3.0 eV. Find the minimum and maximum kinetic energy of the photoelectrons.

The magnetic field associated with a light wave is given, at the origin, by B=B_(0)[sin(3.14xx10^(7))ct +sin(6.28xx10^(7))ct]. If this light falls on a silver plate having a work function fo 4.7 eV, what will be the maximum kinetic energy of the photo electrons? (c=3xx10^(8)ms^(-1),h=6.6xx10^(-34)J-s)

Light of wavelength 4000Å is allowed to fall on a metal surface having work function 2 eV. The maximum velocity of the emitted electrons is (h=6.6xx10^(-34)Js)

Light corresponding to the transition n = 4 to n = 2 in hydrogen atom falls on cesium metal (work function = 1.9 eV) Find the maximum kinetic energy of the photoelectrons emitted

An electromagnetic radiation whose electric component varies with time as E=E_0(1+cos omegat)cos omega_0t(omega=6xx10^(15) "rad"//s, omega_0=2.8 xx10^(14) "rad"//s) is incident on a lithium surface (work function =2.39 eV) . The maximum kinetic energy of a photoelectron liberated from the lithium surface is (h=4.14 x10^(-15) ev-s)