The electric field associated with a monochromatic beam of light becomes zero, `1.2xx10^15` times per second. Find the maximum kinetic energy of the photoelectrons when this light falls on a metal surface whose work function is 2.0eV, `h=6.63xx10^(-34)Js`.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Determine the frequency of the monochromatic beam of light
The electric field associated with the monochromatic beam of light becomes zero `1.2 x 10^15` times per second. Since the electric field becomes zero twice in one cycle (once at the peak and once at the trough), we can find the frequency (ν) of the light using the formula:

\[ \nu = \frac{1.2 \times 10^{15}}{2} \]
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