A small piece of cesium metal `phi=1.9eV` is kept at a distance of 20 cm form a large metal plate having a charge density of `1.0xx 10^-9 C m^-2` on the surface facing the cesium piece. A monochromatic light of wavelength 400nm is incident on the cesium piece. Find the minimum and the maximum kinetic energy of the photoelectrons reaching the large metal plate. Neglect any change in electric field due to the small piece of cesium present.

Explanation

To solve the problem, we need to find the minimum and maximum kinetic energy of the photoelectrons reaching the large metal plate. We will follow these steps:

### Step 1: Calculate the energy of the incident photons
The energy of the incident photons can be calculated using the formula:
\[ E = \frac{hc}{\lambda} \]
Where:
- \( h = 6.63 \times 10^{-34} \, \text{J s} \) (Planck's constant)
- \( c = 3 \times 10^8 \, \text{m/s} \) (speed of light)
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