What is the wavelength of the radiation emitted when the electron in a hydrogen atom jumps from `n = to n = 2`?

Explanation

To find the wavelength of the radiation emitted when the electron in a hydrogen atom jumps from a higher energy level (n = ∞) to n = 2, we can follow these steps:

### Step 1: Determine the energy levels
The energy of an electron in a hydrogen atom at a given principal quantum number \( n \) is given by the formula:
\[ E_n = -\frac{13.6 \, \text{eV}}{n^2} \]
For \( n = 2 \):
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