Light corresponding to the transition `n = 4 to n = 2` in hydrogen atom falls on cesium metal (work function `= 1.9 eV)` Find the maximum kinetic energy of the photoelectrons emitted

Explanation

To solve the problem, we will follow these steps:

### Step 1: Calculate the energy of the photon emitted during the transition from n = 4 to n = 2 in the hydrogen atom.

The energy of the photon (E) corresponding to the transition can be calculated using the formula:

\[
E = 13.6 \, \text{eV} \left( \frac{1}{n_f^2} - \frac{1}{n_i^2} \right)
...