The `Ka` X-ray of molybdenum has wavelength 71 pm. If the energy of a molybdenum atom with a K electron knocked out is 23:32 keV, what will be the energy of this atom when an L electron is knocked out?

Explanation

To solve the problem step by step, we will follow the reasoning provided in the video transcript.

### Step 1: Understand the problem
We are given the wavelength of the Kα X-ray of molybdenum and the energy of a molybdenum atom with a K electron knocked out. We need to find the energy of the atom when an L electron is knocked out.

### Step 2: Identify the energies
Let:
- \( E_K \) = energy of the atom with the K electron knocked out = 23.32 keV
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