The short-wavelength limit shifts by 26 pm when the operating voltage in an X-ray tube is increased to 1.5 times the original value. What was the original value of the operating voltage?

Explanation

To solve the problem, we need to determine the original operating voltage \( V \) of the X-ray tube given that the short-wavelength limit shifts by 26 pm when the voltage is increased to 1.5 times its original value.

### Step-by-Step Solution:

1. **Understanding the relationship**: The short-wavelength limit (cutoff wavelength) \( \lambda_{\text{min}} \) is given by the formula:
\[ \lambda_{\text{min}} = \frac{hc}{eV} \]
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