The electron beam in a colour TV is accelerated through 32 kV and then strikes the screen. What is the wavelength of the most energetic X-ray photon?

Explanation

To find the wavelength of the most energetic X-ray photon produced when an electron beam is accelerated through a potential difference of 32 kV, we can follow these steps:

### Step 1: Convert the potential difference to energy
The potential difference (V) is given as 32 kV. We need to convert this to joules. The energy (E) in electron volts can be expressed as:
\[ E = V \]
Since 1 eV = 1.6 × 10^-19 joules, we can convert 32 kV to electron volts:
\[ E = 32 \, \text{kV} = 32 \times 10^3 \, \text{eV} = 32 \times 10^3 \times 1.6 \times 10^{-19} \, \text{J} \]

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