Suppose a monochromatic X-ray beam of wavelength 100 pm is sent through a Young's double slit and the interference pattern is observed on a photographic plate placed 40 cm away from the slit. What should be the separation between the slits so that the successive maxima on the screen are separated by a distance of 0.1 mm?

Explanation

To solve the problem step by step, we will use the formula for fringe width in a Young's double slit experiment. The formula is:

\[ \beta = \frac{\lambda D}{d} \]

where:
- \(\beta\) is the fringe width (distance between successive maxima),
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