A p-type semoconductor has acceptor levels `57meV `above the valence band. Find the maximum wavelength of light which can create a hole.

Explanation

To find the maximum wavelength of light that can create a hole in a p-type semiconductor with an acceptor level of 57 meV above the valence band, we can follow these steps:

### Step 1: Understand the Energy Levels
In a p-type semiconductor, the acceptor level is located just above the valence band. The energy required to excite an electron from the valence band to the acceptor level is given as 57 meV.

### Step 2: Convert Energy from MeV to Joules
We need to convert the energy from milli-electron volts (meV) to joules (J) for our calculations. The conversion factor is:
1 eV = 1.6 × 10^(-19) J.
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