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Find the curent through the battery in e...

Find the curent through the battery in each of the circuit shown in figure

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Both diodes forward biased.Thus the net diode resistance is 0.
`I = (5)/((10xx10)/(10+10)) = (5)/(5) = 1A`
One diode is forwad biased and other is reverse biased.
Current passes the forward biased diode only.
`I =(V)/(R_net ) = (5)/(10+0) = 0.5A`
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