Find the maximum energy that a beta particle can have in the following decay
`^176 Lu rarr ^176 Hf + e + vec v`.
Alomic mass of `^176 Lu` is `175.942694 u` and that of `^176 Hf` is `175.941420 u`.

Explanation

To find the maximum energy that a beta particle can have in the decay of Lutetium-176 to Hafnium-176, we can follow these steps:

### Step 1: Write down the decay equation
The decay process is given as:
\[ ^{176}Lu \rightarrow ^{176}Hf + e^- + \bar{\nu} \]
where \( e^- \) is the beta particle (electron) and \( \bar{\nu} \) is the anti-neutrino.
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