Home
Class 12
PHYSICS
P^32 beta-decays to S^32.Find the sum of...

`P^32` beta-decays to `S^32`.Find the sum of the energy of the antineutrino and the kinetic energy of the `beta`-particle. Neglect the recoil of the daughter nucleus. Atomic mass of `P^32=31.974 u` and that of `S^32=31.972 u`.

Text Solution

Verified by Experts

The correct Answer is:
A

`p^(32) rarr S^(32) + _1v^0 + _(-1)beta^0`
Energy of antineutrino and `beta-particle`
`= (31.974 - 31.972)u`
`= 0.002u`
`=0.002 xx 931= 11.862 MeV` .
Promotional Banner

Topper's Solved these Questions

  • THE NUCLEOUS

    HC VERMA ENGLISH|Exercise Short answer|12 Videos
  • THE NUCLEOUS

    HC VERMA ENGLISH|Exercise Objective 2|10 Videos
  • SPEED OF LIGHT

    HC VERMA ENGLISH|Exercise Question for short Answer|5 Videos
  • THE SPECIAL THEORY OF RELATIVITY

    HC VERMA ENGLISH|Exercise Short answer|2 Videos

Similar Questions

Explore conceptually related problems

A nucleus of mass 220 amu in the free state decays to emit an alpha -particle . Kinetic energy of the alpha -particle emitted is 5.4 MeV. The recoil energy of the daughter nucleus is

Consider the beta decay ^198 Au rarr ^198 Hg ** + Beta^(-1) + vec v . where ^198 Hg^** represents a mercury nucleus in an excited state at energy 1.088 MeV above the ground state. What can be the maximum kinetic energy of the electron emitted? The atomic mass of ^198 Au is 197.968233 u and that of ^198 Hg is 197.966760 u .

Find the maximum energy that a beta particle can have in the following decay ^176 Lu rarr ^176 Hf + e + vec v . Alomic mass of ^176 Lu is 175.942694 u and that of ^176 Hf is 175.941420 u .

A nucleus of mass 218 amu is in free state decays to emit an alpha -particle. Kinetic energy of alpha -particle emitted is 6.7Mev. The recoil energy in (MeV) emitted by the daughter nucleus is

Calculate the volume of 320 g of SO_2 at S.T.P. (Atomic mass : S = 32 and O = 16).

Calculate the kinetic energy of beta -particles and the radiation frequencies corresponding to the gamma -decays shown in figure. Given, mass of ._12Mg^27 atom =26.991425 amu and mass of ._13Al^27 atom = 26.990080 amu

The beta -decay process, discovered around 1900 , is basically the decay of a neutron (n) , In the laboratory, a proton (p) and an electron (e^(-)) are observed as the decay products of the neutron. Therefore, considering the decay of a neutron as a tro-body dcay process, it was observed that the electron kinetic energy has a continuous spectrum. Considering a three-body decay process i.e., n rarr p + e^(-)+overset(-)v_(e ) , around 1930 , Pauli explained the observed electron energy spectrum. Assuming the anti-neutrino (overset(-)V_(e )) to be massless and possessing negligible energy, and neutron to be at rest, momentum and energy conservation principles are applied. From this calculation, the maximum kinetic energy of the electron is 0.8xx10^(6)eV . The kinetic energy carried by the proton is only the recoil energy. If the anti-neutrino has a mass of 3eV//c^(2) (where c is the speed of light) instead of zero mass, what should be the range of the kinetic energy, K of the electron?

Neon-23 decays in the following way, _10^23Nerarr_11^23Na+ _(-1)^0e+barv Find the minimum and maximum kinetic energy that the beta particle (_(-1)^0e) can have. The atomic masses of ^23Ne and ^23 Na are 22.9945u and 22.9898u , respectively.

Neon-23 decays in the following way, ._10^23Nerarr_11^23Na+ _(-1)^0e+barv Find the minimum and maximum kinetic energy that the beta particle (._-1^0e) can have. The atomic masses of .^23Ne and .^23 Na are 22.9945u and 22.9898u , respectively.

The beta - decay process , discovered around 1900 , is basically the decay of a neutron n . In the laboratory , a proton p and an electron e^(bar) are observed as the decay product of neutron. Therefore considering the decay of neutron as a two- body decay process, it was predicted theoretically that the kinetic energy of the electron should be a constant . But experimentally , it was observed that the electron kinetic energy has continuous spectrum Considering a three- body decay process , i.e. n rarr p + e^(bar) + bar nu _(e) , around 1930 , Pauli explained the observed electron energy spectrum. Assuming the anti-neutrino (bar nu_(e)) to be massaless and possessing negligible energy , and the neutrino to be at rest , momentum and energy conservation principle are applied. From this calculation , the maximum kinetic energy of the electron is 0.8 xx 10^(6) eV The kinetic energy carried by the proton is only the recoil energy. If the - neutrono had a mass of 3 eV// c^(2) (where c is the speed of light ) insend of zero mass , what should be the range of the kinectic energy K. of the electron ?

HC VERMA ENGLISH-THE NUCLEOUS-Exercise
  1. Show that the minimum energy needed to sepatate a proton from a nucleu...

    Text Solution

    |

  2. Calculate the minimum energy needed to separate a neutron form a nucle...

    Text Solution

    |

  3. P^32 beta-decays to S^32.Find the sum of the energy of the antineutrin...

    Text Solution

    |

  4. A free neutron beta-decays to a proton weth a half-life of 14 minutes ...

    Text Solution

    |

  5. Complete the following decay schemes. (a)Ra88^226 rarr alpha + (b)O...

    Text Solution

    |

  6. In the decay Cu^64 rarr Ni^64 + e^+ + v, the maximum kinetic energy ...

    Text Solution

    |

  7. Potassium-40 can decay in three modes .It can decay by beta^(-) - emis...

    Text Solution

    |

  8. Lithium (Z=3) has two stable isotopes Li^6and Li^7.When neutrons are b...

    Text Solution

    |

  9. The masses of "^11C and "^11B are respectively 11.0114 u and 11.0093 u...

    Text Solution

    |

  10. Th^228emits an alpha particle to reduce to Ra^224.Calculate the kineti...

    Text Solution

    |

  11. Calculate the maximum kinetic energy of the beta particle emitted in t...

    Text Solution

    |

  12. The decay constant of Hg80^197(electron capature to Au79^197)is 1.8xx1...

    Text Solution

    |

  13. The half-life of Au^198 is 2.7 days.(a) Find the activity of a sample...

    Text Solution

    |

  14. Radioactive 138I has a half-life of 8.0 days .A sample containing 138I...

    Text Solution

    |

  15. The decay constant of U^238is 4.9xx10^-18 s^-1.(a) What is the avarage...

    Text Solution

    |

  16. A certain sample of a radioactive marerial decays at the rate of 500 p...

    Text Solution

    |

  17. the count rate from a radioactive sample falls from 4.0xx10^6per secon...

    Text Solution

    |

  18. The half-life of Ra^226 is 1602 y.Calculate the activity of 0.1g of Ra...

    Text Solution

    |

  19. The half-life of a radioisotope is 10 h . Find the total number of dis...

    Text Solution

    |

  20. The selling rate of a radioactive isotope is decided by its activity. ...

    Text Solution

    |