In the decay `Cu^64 rarr Ni^64 + e^+ + v`,
the maximum kinetic energy carried by the netrino which was emitted together with a positron of kinetic energy 0.150 meV? (a) what is the energy of the neutrino which was emitted togather with a positron of kinetic energy 0.150 MeV ? .(b)What is the momentum of this neutrino in kg m `s^(-1)`?Use the formula applicable to photon.

Answer

A, B

Explanation

``^(64)C_u rarr ^(64)Ni + -e + v`
Emission of neutrino is along with a
positron emission.
(a) Energy of positron = 0.650 MeV
Energy of Neutrino
`= 0.650 - KE of given positron`
`= 0.650 - 0.150`
`= 0.5 MeV = 500 KeV`.
(b) Momentum of Nutrino
`=(500 x 1.6 xx 10^(-19))/(3 xx 10^(8)) xx 10^3J `
`= 2.67 xx 10^(-27) Kg//ms` .