Suppose Swrglok (heaven) is in constant motion at a speed of 0.9999c with respect to the earth. According to the earth,s frame , how much time passes on the earth before one day passes on Swarglok?

Explanation

Given ` v = 0.9999 C, `
`Delta t = One day in earth`
` Delta t ' = One day in heaven `
` v = 1 / (sqrt 1 - v^(2) / c^(2)) `
` = 1 / (sqrt 1 - (0.9999)^(2) c^(2) / c^(2) )`
` 1 / 0.014141782 = 70.712 `
Delta t' = v Delta t `
`Hence Delta t ' = 70.7 days in heaven ` .