Manganese forms non-stoichiometric oxides having the general formula `MnO_x`. The value of `x` for the compound that analyzed `64%` by mass Mn :

Manganese forms non-stoichiometric oxides having the gereral formula formula MnO_x . The value of x for the compound that analyzed 64% by mass mn :

Manganese forms nonstoichiometric oxides having the general formula MnOn. Find the value of n for the compound that analysed 63.7% Mn.

An element X occurs in short period having configuration ns^(2)np^(1) . The formula and nature of its oxide is:

A gas is found to have molecular formula (CO)_(x) . Its vapour density is 70, the value of x must be:-

X = number of compounds having - I group directly attached to benzene. Find the value of X ?

An element X forms two oxides. Formula of the first oxide is XO_(2) . The first contains 50% of oxygen. If the second oxide contains 60% oxygen, the formula of the second oxide is

If the anions (X) form hexagonal closed packing and cations (Y) occupy only 3/8th of octahedral voids in it, then the general formula of the compound is

Chlorine atom, in its third excited state, react with fluorine to form compound X. the formula and shape of X are

Oxidation number is the charge which an atom of an element has in its ion or appears to have when present in the combined state. It is also called oxidation state. Oxidation number of any atom in the elementary state is zero. Oxidation number of a monoatomic ion is equal to the charge on it. In compounds of metals with non metals, metals have positive oxidation number while non metals have negative oxidation numbers. In compounds of two difference elements, the more electronegative element has negative oxidation number whereas the other has positive oxidation number. In complex ions, the sum of the oxidation number of all the atoms is equal to the charge on the ion. If a compound contains two or more atoms of the same element, they may have same or different oxidation states according as their chemical bonding is same or different. A compound of Xe and F is found to have 53.3% Xe (atomic weight =133). Oxidation number of Xe in this compound is

The non- stoichiometric compound Fe_(0.94)O is formed when x% of Fe^(2+) ions are replaced by as many 2//3 Fe^(3+) ions The value of x is: