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For the reaction, 2Fe(NO3)3+3Na2CO3rarrF...

For the reaction, `2Fe(NO_3)_3+3Na_2CO_3rarrFe_2(CO_3)_3+6NaNO_3` initially `2.5` mole of `Fe(NO_3)_3 and 3.6` mole of `Na_2 CO_3` are taken. If `6.3` mole of `NaNO_3` is obtained then % yield of given reaction is :

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