A gaseous mixture of propane and butane of volume 3 litre on complete combustion produces `11.0` litre `CO_2` under standard conditions of temperature and pressure. The ratio of volume of butane to propane is :

6 litre of mixture of methane and propane on complete combustion gives 7 litre of CO_(2) . Find out the composition of the mixture ?

A 3 L gas mixture of propane (C_(3)H_(8)) and butane (C_(4)H_(10)) on complete combustion at 25 C produced 10 L CO_(2.) Assuming constant P and T conditions what was volume of butane present in initial mixture?

If 1 litre of N2 at 27^(@)C and 760 mm Hg contains N molecules, 4 litres of O_(2) under the same conditions of temperature and pressure, shall contain

3 L mixture of propane and butane on complete combustion at 298 K gave 10 L CO_2 Calculate the compostion of the gas mixture.

The number of mole of nitrogen in one litre of air containing 10% nitrogen by volume, under standard conditions, is

If one mole of a gas A (mol.wt-40) occupies a volume of 20 litres, under the same conditions of temperature and pressure the volume occupied by 2 moles of gas B (mol.wt=80) is

The ratio of the mass of a certain volume of gas to the mass of an equal volume of hydrogen under the same conditions of temperature and pressure is known as_______

A gas mixture of 4 litres of ethylene and methane on complete combustion at 25^(@)C produces 6 litres of CO_(2) . Find out the amount of heat evolved on burning one litre of the gas mixture. The heats of combustion of ethylene and methane are -1464 and -976 KJ mol^(-1) at 25^(@)C

when gases react together their reacting volumes bear a simple ratio to each other under the same conditions of temperature and pressure . Who proposed this law ?

The volumes of gases A, B, C and D are in the ratio, 1:2:2:4 under the same conditions of temperature and pressure. If this ratio of gas volumes refers to the reactants and products of a reaction, which gas law is being observed?